Regenerative switching circuits such as **Astable Multivibrators** are the most commonly used type of relaxation oscillator because not only are they simple, reliable and ease of construction they also produce a constant square wave output waveform.

Unlike the Monostable Multivibrator or the Bistable Multivibrator we looked at in the previous tutorials that require an “external” trigger pulse for their operation, the **Astable Multivibrator** has automatic built in triggering which switches it continuously between its two unstable states both set and reset.

The **Astable Multivibrator** is another type of cross-coupled transistor switching circuit that has **NO** stable output states as it changes from one state to the other all the time. The astable circuit consists of two switching transistors, a cross-coupled feedback network, and two time delay capacitors which allows oscillation between the two states with no external triggering to produce the change in state.

In electronic circuits, astable multivibrators are also known as **Free-running Multivibrator** as they do not require any additional inputs or external assistance to oscillate. Astable oscillators produce a continuous square wave from its output or outputs, (two outputs no inputs) which can then be used to flash lights or produce a sound in a loudspeaker.

The basic transistor circuit for an **Astable Multivibrator** produces a square wave output from a pair of grounded emitter cross-coupled transistors. Both transistors either NPN or PNP, in the multivibrator are biased for linear operation and are operated as Common Emitter Amplifiers with 100% positive feedback.

This configuration satisfies the condition for oscillation when: ( βA = 1∠ 0^{o} ). This results in one stage conducting “fully-ON” (Saturation) while the other is switched “fully-OFF” (cut-off) giving a very high level of mutual amplification between the two transistors. Conduction is transferred from one stage to the other by the discharging action of a capacitor through a resistor as shown below.

Assume that transistor, TR_{1} has just switched “OFF” (cut-off) and its collector voltage is rising towards Vcc, meanwhile transistor TR_{2} has just turned “ON”. Plate “A” of capacitor C1 is also rising towards the +6 volts supply rail of Vcc as it is connected to the collector of TR_{1} which is now cut-off. Since TR_{1} is in cut-off, it conducts no current so there is no volt drop across load resistor R_{1}.

The other side of capacitor, C1, plate “B”, is connected to the base terminal of transistor TR_{2} and at 0.6v because transistor TR_{2} is conducting (saturation). Therefore, capacitor C1 has a potential difference of +5.4 volts across its plates, (6.0 – 0.6v) from point A to point B.

Since TR_{2} is fully-on, capacitor C_{2} starts to charge up through resistor R_{2} towards Vcc. When the voltage across capacitor C_{2} rises to more than 0.6v, it biases transistor TR_{1} into conduction and into saturation.

The instant that transistor, TR_{1} switches “ON”, plate “A” of the capacitor which was originally at Vcc potential, immediately falls to 0.6 volts. This rapid fall of voltage on plate “A” causes an equal and instantaneous fall in voltage on plate “B” therefore plate “B” of C1 is pulled down to -5.4v (a reverse charge) and this negative voltage swing is applied the base of TR_{2} turning it hard “OFF”. One unstable state.

Transistor TR_{2} is driven into cut-off so capacitor C1 now begins to charge in the opposite direction via resistor R3 which is also connected to the +6 volts supply rail, Vcc. Thus the base of transistor TR_{2} is now moving upwards in a positive direction towards Vcc with a time constant equal to the C1 x R3 combination.

However, it never reaches the value of Vcc because as soon as it gets to 0.6 volts positive, transistor TR_{2} turns fully “ON” into saturation. This action starts the whole process over again but now with capacitor C2 taking the base of transistor TR_{1} to -5.4v while charging up via resistor R2 and entering the second unstable state.

Then we can see that the circuit alternates between one unstable state in which transistor TR_{1} is “OFF” and transistor TR_{2} is “ON”, and a second unstable in which TR_{1} is “ON” and TR_{1} is “OFF” at a rate determined by the RC values. This process will repeat itself over and over again as long as the supply voltage is present.

The amplitude of the output waveform is approximately the same as the supply voltage, Vcc with the time period of each switching state determined by the time constant of the RC networks connected across the base terminals of the transistors. As the transistors are switching both “ON” and “OFF”, the output at either collector will be a square wave with slightly rounded corners because of the current which charges the capacitors. This could be corrected by using more components as we will discuss later.

If the two time constants produced by C2 x R2 and C1 x R3 in the base circuits are the same, the mark-to-space ratio ( t1/t2 ) will be equal to one-to-one making the output waveform symmetrical in shape. By varying the capacitors, C1, C2 or the resistors, R2, R3 the mark-to-space ratio and therefore the frequency can be altered.

We saw in the RC Discharging tutorial that the time taken for the voltage across a capacitor to fall to half the supply voltage, 0.5Vcc is equal to 0.69 time constants of the capacitor and resistor combination. Then taking one side of the astable multivibrator, the length of time that transistor TR_{2} is “OFF” will be equal to 0.69T or 0.69 times the time constant of C1 x R3. Likewise, the length of time that transistor TR_{1} is “OFF” will be equal to 0.69T or 0.69 times the time constant of C2 x R2 and this is defined as.

Where, R is in Ω’s and C in Farads.

By altering the time constant of just one RC network the mark-to-space ratio and frequency of the output waveform can be changed but normally by changing both RC time constants together at the same time, the output frequency will be altered keeping the mark-to-space ratios the same at one-to-one.

If the value of the capacitor C1 equals the value of the capacitor, C2, C1 = C2 and also the value of the base resistor R2 equals the value of the base resistor, R3, R2 = R3 then the total length of time of the **Multivibrators** cycle is given below for a symmetrical output waveform.

Where, R is in Ω’s, C is in Farads, T is in seconds and ƒ is in Hertz.

and this is known as the “Pulse Repetition Frequency”. So **Astable Multivibrators** can produce TWO very short square wave output waveforms from each transistor or a much longer rectangular shaped output either symmetrical or non-symmetrical depending upon the time constant of the RC network as shown below.

An **Astable Multivibrators** circuit is required to produce a series of pulses at a frequency of 500Hz with a mark-to-space ratio of 1:5. If R2 = R3 = 100kΩ’s, calculate the values of the capacitors, C1 and C2 required.

and by rearranging the formula above for the periodic time, the values of the capacitors required to give a mark-to-space ratio of 1:5 are given as:

The values of 4.83nF and 24.1nF respectively, are calculated values, so we would need to choose the nearest preferred values for C1 and C2 allowing for the capacitors tolerance. In fact due to the wide range of tolerances associated with the humble capacitor the actual output frequency may differ by as much as ±20%, (400 to 600Hz in our simple example) from the actual frequency needed.

If we require the output astable waveform to be non-symmetrical for use in timing or gating type circuits, etc, we could manually calculate the values of R and C for the individual components required as we did in the example above. However, when the two R’s and C´s are both equal, we can make our life a little bit easier for ourselves by using tables to show the astable multivibrators calculated frequencies for different combinations or values of both R and C. For example,

Res. | Capacitor Values | ||||||||

1nF | 2.2nF | 4.7nF | 10nF | 22nF | 47nF | 100nF | 220nF | 470nF | |

1.0kΩ | 714.3kHz | 324.6kHz | 151.9kHz | 71.4kHz | 32.5kHz | 15.2kHz | 7.1kHz | 3.2kHz | 1.5kHz |

2.2kΩ | 324.7kHz | 147.6kHz | 69.1kHz | 32.5kHz | 14.7kHz | 6.9kHz | 3.2kHz | 1.5kHz | 691Hz |

4.7kΩ | 151.9kHz | 69.1kHz | 32.3kHz | 15.2kHz | 6.9kHz | 3.2kHz | 1.5kHz | 691Hz | 323Hz |

10kΩ | 71.4kHz | 32.5kHz | 15.2kHz | 7.1kHz | 3.2kHz | 1.5kHz | 714Hz | 325Hz | 152Hz |

22kΩ | 32.5kHz | 14.7kHz | 6.9kHz | 3.2kHz | 1.5kHz | 691Hz | 325Hz | 147Hz | 69.1Hz |

47kΩ | 15.2kHz | 6.9kHz | 3.2kHz | 1.5kHz | 691Hz | 323Hz | 152Hz | 69.1Hz | 32.5Hz |

100kΩ | 7.1kHz | 3.2kHz | 1.5kHz | 714Hz | 325Hz | 152Hz | 71.4Hz | 32.5Hz | 15.2Hz |

220kΩ | 3.2kHz | 1.5kHz | 691Hz | 325Hz | 147Hz | 69.1Hz | 32.5Hz | 15.2Hz | 6.9Hz |

470kΩ | 1.5kHz | 691Hz | 323Hz | 152Hz | 69.1Hz | 32.5Hz | 15.2Hz | 6.6Hz | 3.2Hz |

1MΩ | 714Hz | 325Hz | 152Hz | 71.4Hz | 32.5Hz | 15.2Hz | 6.9Hz | 3.2Hz | 1.5Hz |

Pre-calculated frequency tables can be very useful in determining the required values of both R and C for a particular symmetrical output frequency without the need to keep recalculating them every time a different frequency is required.

By changing the two fixed resistors, R_{2} and R_{3} for a dual-ganged potentiometer and keeping the values of the capacitors the same, the frequency from the **Astable Multivibrators** output can be more easily “tuned” to give a particular frequency value or to compensate for the tolerances of the components used.

For example, selecting a capacitor value of 10nF from the table above. By using a 100kΩ’s potentiometer for our resistance, we would get an output frequency that can be fully adjusted from slightly above 71.4kHz down to 714Hz, some 3 decades of frequency range. Likewise a capacitor value of 47nF would give a frequency range from 152Hz to well over 15kHz.

An **Astable Multivibrator** circuit is constructed using two timing capacitors of equal value of 3.3uF and two base resistors of value 10kΩ. Calculate the minimum and maximum frequencies of oscillation if a 100kΩ dual-gang potentiometer is connected in series with the two resistors.

with the potentiometer at 0%, the value of the base resistance is equal to 10kΩ.

with the potentiometer at 100%, the value of the base resistance is equal to 10kΩ + 100kΩ = 110kΩ.

Then the output frequency of oscillation for the astable multivibrator can be varied from between 2.0 and 22 Hertz.

When selecting both the resistance and capacitance values for reliable operation, the base resistors should have a value that allows the transistor to turn fully “ON” when the other transistor turns “OFF”. For example, consider the circuit above. When transistor TR_{2} is fully “ON”, (saturation) nearly the same voltage is dropped across resistor R3 and resistor R4.

If the transistor being used has a current gain, β of 100 and the collector load resistor, R4 is equal to say 1kΩ the maximum base resistor value would therefore be 100kΩ. Any higher and the transistor may not turn fully “ON” resulting in the multivibrator giving erratic results or not oscillate at all. Likewise, if the value of the base resistor is too low the transistor may not switch “OFF” and the multivibrator would again not oscillate.

An output signal can be obtained from the collector terminal of either transistor in the Astable Multivibrators circuit with each output waveform being a mirror image of itself. We saw above that the leading edge of the output waveform is slightly rounded and not square due to the charging characteristics of the capacitor in the cross-coupled circuit.

But we can introduce another transistor into the circuit that will produce an almost perfectly square output pulse and which can also be used to switch higher current loads or low impedance loads such as LED’s or loudspeakers, etc without affecting the operation of the actual astable multivibrator. However, the down side to this is that the output waveform is not perfectly symmetrical as the additional transistor produces a very small delay. Consider the two circuits below.

An output with a square leading edge is now produced from the third transistor, TR_{3} connected to the emitter of transistor, TR_{2}. This third transistor switches “ON” and “OFF” in unison with transistor TR_{2}. We can use this additional transistor to switch Light Emitting Diodes, Relays or to produce a sound from a Sound Transducer such as a speaker or piezo sounder as shown above.

The load resistor, Rx needs to be suitably chosen to take into account the forward volt drops and to limit the maximum current to about 20mA for the LED circuit or to give a total load impedance of about 100Ω’s for the speaker circuit. The speaker can have any impedance less than 100Ω’s. By connecting an additional transistor, TR_{4} to the emitter circuit of the other transistor, TR_{1} in a similar fashion we can produce an astable multivibrator circuit that will flash two sets of lights or LED’s from one to the other at a rate determined by the time constant of the RC timing network.

In the next tutorial about Waveforms and Signals, we will look at the different types of **Astable Multivibrators** that are used to produce a continuous output waveform. These circuits known as relaxation oscillators produce either a square or rectangular wave at their outputs for use in sequential circuits as either a clock pulse or timing signal. These types of circuits are called Waveform Generators.

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it was very easy to understand Astable multivibrator

dear sir/mom

which you said the concept not understand.please explain the concept send to my email

its very easy to understand but in need to know applications of astable multivibrator too

As explained in the tutorial, astable’s produce a continuous square wave waveform which can be used in a variety of applications from timing signals at high frequencies to flashing lights at low frequencies.

Hi there, love your site.

I just built the oscillator and indeed got a rounded rising edge on the collectors’ outputs. I tried adding a third transistor as you suggested to make the signal more square-like. It didn’t work with the components connected as shown on the diagram. However, as soon as I connected the third transistor’s base to either collector, I got an almost perfect square. Any ideas as of why this happened?

Without knowing your circuit, possibly resistor R4 is too high, lack of Base drive on TR3, transistor TR2 no switching fully ON or OFF, etc. Try different values.

In the tutorial you said that collectors are the outputs for the signals. When I saw the third transistor conected to the emitter, I was rather upset because I thought it would produce an umbalanced reference on the second transistor and hence no output at all. Regards

TR2 is connected as a switch to drive the base of TR3.

Hello

Where the value of 0.69 came from? I’ve looked to RC Discharging tutorial and haven’t seen it. From simulation in LTspice IV (tries and errors method) I’ve got more like 1.88/2=0.94. For me it’s quite a difference in the value.

f = 1/T where T = t1 + t2, the charging capacitor voltage is a function of time. The two transistors alternate being saturated (Vce ≈ 0) and cut-off (Vce ≈ Vcc) with each being in the opposite state of the other charging and discharging the capacitors alternately. The timing resistor and capacitor are in series across the supply and transistor Base, triggering the transistor when the charge on the capacitors plates is greater than e^-t/(RC) which equals ln(2)RC or 0.693RC

Hello. Many thanks for your explanations. What I understand is that the capacitor wants to raise from -5 to +5 V (VR2 reaching -10V). But halfway (half of the capacity, thus 0.693*T), when it reaches 0.6V, Q2 suddenly opens (so this side of the capacitor remains at 0.6V; the curve has an angle).

The value of 0.6 from the base of the transistor TR2, for it is the ddp between the base and the emitter. The transistor leads only when the base is at 0.6 V, compensating the voltage of 0.6 of the junction between the base and the emitter. See the handout of transistors.

sir…….I has connected all the circuit but the led glows continuously ,the led has to blink in astable mode it didnt blink what is the problem and why did the output has not come say please……….

You have connected the circuit incorrectly, or the oscillation frequency to too high.

now i knw the operetion of an Astable

I have a simple Astable multivibrator circuit with the following components.

2 x 10k res.

2 x 100 uF caps

2 x LED’s

BC108 (or 2N2222) transistors

(It only uses the 2 resistors above)

Can I use 12v, 9v or 4.5v as power supply to this without damaging the components?

What do I have to change to slow down the blink rate of this circuit and/or improve the circuit. (Calculus is Greek to me)

What is the electricity usage (watts) of this circuit (Try to save electricity, I am running this constantly 24 x 7 connected to a cellphone charger for power)

Hello Clark, The circuit will work perfectly well from a 4.5v, 9v or 12v supply, but the supply voltage has an effect on the RC time constant of the circuit increasing it as the voltage increases because the capacitor has to charge to a high value. To slow down the blink rate as you call it, increase the values of the capacitors, resistors, or both. To improve the circuit and reduce the power consumption use extra resistors, 1kohms or above in series with the LEDs to limit their current.

Many thanks for your speedy reply Wayne. I will play with it and see what the results are. What is the RC time you mentioned? I do not know much about electronic abbreviations. You did not mention anything about the use of cellphone chargers as a power supply. Is it a good thing to use them in the long run (power saving)?

I have used a 9v battery with a 380 ohm resistor and a bi-color LED (red/green) to simplify or by-pass building a circuit board and obtain a red/green blinking effect, but the battery was totally drained whithin 24 hours. How can I improve the battery life in such a circuit? Will I have a longer battery life with a 3v battery or not? I suppose that with a higher voltage, the LED will draw more power too, am I correct, or am I swinging the cat by it’s tail?

Hello Clark, cellphone chargers are mains powered devices then battery power consumption is not a problem. What is the problem is the 380 ohm resistors you are using, that’s where the powers going. Assuming a combined forward voltage drop of about 2.0V across the LED and saturated transistor together, then (9v-2v)/380 ohm gives about 18mA through the LED. Your LEDs will be nice and bright but they are draining your battery. Increase the value of this resistor until the LEDs are as dim as you want it to be. As said before, 1kohm or above.

Hey guys you should know I am trying to build an FM transmitter and I am running into problems. But thanks to this I have one less problem to worry about. You see I want it to broadcast in between 108 MHZ to 88 and I am getting farther every day. The reason I need it is because every FM transmitter needs a VFO so thanks. 🙂

Thank you for the clear tutorial. Is there anyway to predict which “side” of the astable multivibrator will output high first? I am hoping to use two multivibrators in parallel but I need their outputs to be in phase every time the circuit is powered on. The tests I’ve done use ganged potentiometers for R2 and R3 (in your diagram) for each astable multivibrator, and power one speaker. Once their frequency is similar enough, they sound like they almost fall into phase naturally because the apparent volume increases. Will adjusting R1 and R4 help force a predictable output? Any help is welcome,

Thank you.

If you look at using the multivibrator as a set/reset flip flop, you can actually feed it a clock source and they should stay in synch. I would probably build a third to act as the clock and then have the pair operating as S/R flip flops. Although it would actually be a lot easier to accomplish the same thing with three inverters one a 74xx series chip.

this is a very easy to understand……….

0.69 comes from ln0.5

That’s right. You can even simulate it on:

http://www.cirvirlab.com/simulation/Relaxation_Oscillator_Online_Simulation.php