The **Colpitts Oscillator**, named after its inventor Edwin Colpitts is another type of LC oscillator design.

In many ways, the Colpitts oscillator is the exact opposite of the **Hartley Oscillator** we looked at in the previous tutorial. Just like the Hartley oscillator, the tuned tank circuit consists of an LC resonance sub-circuit connected between the collector and the base of a single stage transistor amplifier producing a sinusoidal output waveform.

The basic configuration of the **Colpitts Oscillator** resembles that of the *Hartley Oscillator* but the difference this time is that the centre tapping of the tank sub-circuit is now made at the junction of a “capacitive voltage divider” network instead of a tapped autotransformer type inductor as in the Hartley oscillator.

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Colpitts Oscillator

Tank Circuit

Tank Circuit

The Colpitts oscillator uses a capacitive voltage divider network as its feedback source. The two capacitors, C1 and C2 are placed across a single common inductor, L as shown. Then C1, C2 and L form the tuned tank circuit with the condition for oscillations being: X_{C1} + X_{C2} = X_{L}, the same as for the Hartley oscillator circuit.

The advantage of this type of capacitive circuit configuration is that with less self and mutual inductance within the tank circuit, frequency stability of the oscillator is improved along with a more simple design.

As with the Hartley oscillator, the Colpitts oscillator uses a single stage bipolar transistor amplifier as the gain element which produces a sinusoidal output. Consider the circuit below.

The emitter terminal of the transistor is effectively connected to the junction of the two capacitors, C1 and C2 which are connected in series and act as a simple voltage divider. When the power supply is firstly applied, capacitors C1 and C2 charge up and then discharge through the coil L. The oscillations across the capacitors are applied to the base-emitter junction and appear in the amplified at the collector output.

Resistors, R1 and R2 provide the usual stabilizing DC bias for the transistor in the normal manner while the additional capacitors act as a DC-blocking bypass capacitors. A radio-frequency choke (RFC) is used in the collector circuit to provide a high reactance (ideally open circuit) at the frequency of oscillation, ( ƒr ) and a low resistance at DC to help start the oscillations.

The required external phase shift is obtained in a similar manner to that in the Hartley oscillator circuit with the required positive feedback obtained for sustained undamped oscillations. The amount of feedback is determined by the ratio of C1 and C2. These two capacitances are generally “ganged” together to provide a constant amount of feedback so that as one is adjusted the other automatically follows.

The frequency of oscillations for a Colpitts oscillator is determined by the resonant frequency of the LC tank circuit and is given as:

where C_{T} is the capacitance of C1 and C2 connected in series and is given as:.

The configuration of the transistor amplifier is of a Common Emitter Amplifier with the output signal 180^{o} out of phase with regards to the input signal. The additional 180^{o} phase shift require for oscillation is achieved by the fact that the two capacitors are connected together in series but in parallel with the inductive coil resulting in overall phase shift of the circuit being zero or 360^{o}.

The amount of feedback depends on the values of C1 and C2. We can see that the voltage across C1 is the the same as the oscillators output voltage, Vout and that the voltage across C2 is the oscillators feedback voltage. Then the voltage across C1 will be much greater than that across C2.

Therefore, by changing the values of capacitors, C1 and C2 we can adjust the amount of feedback voltage returned to the tank circuit. However, large amounts of feedback may cause the output sine wave to become distorted, while small amounts of feedback may not allow the circuit to oscillate.

Then the amount of feedback developed by the Colpitts oscillator is based on the capacitance ratio of C1 and C2 and is what governs the the excitation of the oscillator. This ratio is called the “feedback fraction” and is given simply as:

A **Colpitts Oscillator** circuit having two capacitors of 24nF and 240nF respectively are connected in parallel with an inductor of 10mH. Determine the frequency of oscillations of the circuit, the feedback fraction and draw the circuit.

The oscillation frequency for a Colpitts Oscillator is given as:

As the colpitts circuit consists of two capacitors in series, the total capacitance is therefore:

The inductance of the inductor is given as 10mH, then the frequency of oscillation is:

The frequency of oscillations for the Colpitts Oscillator is therefore 10.8kHz with the feedback fraction given as:

Just like the previous Hartley Oscillator, as well as using a bipolar junction transistor (BJT) as the oscillators active stage, we can also an operational amplifier, (op-amp). The operation of an **Op-amp Colpitts Oscillator** is exactly the same as for the transistorised version with the frequency of operation calculated in the same manner. Consider the circuit below.

Note that being an inverting amplifier configuration, the ratio of R2/R1 sets the amplifiers gain. A minimum gain of 2.9 is required to start oscillations. Resistor R3 provides the required feedback to the LC tank circuit.

The advantages of the **Colpitts Oscillator** over the Hartley oscillators are that the Colpitts oscillator produces a more purer sinusoidal waveform due to the low impedance paths of the capacitors at high frequencies. Also due to these capacitive reactance properties the FET based Colpitts oscillator can operate at very high frequencies. Of course any op-amp or FET used as the amplifying device must be able to operate at the required high frequencies.

Then to summarise, the **Colpitts Oscillator** consists of a parallel LC resonator tank circuit whose feedback is achieved by way of a capacitive divider. Like most oscillator circuits, the Colpitts oscillator exists in several forms, with the most common form being the transistor circuit above.

The centre tapping of the tank sub-circuit is made at the junction of a “capacitive voltage divider” network to feed a fraction of the output signal back to the emitter of the transistor. The two capacitors in series produce a 180^{o} phase shift which is inverted by another 180^{o} to produce the required positive feedback. The oscillating frequency which is a purer sine-wave voltage is determined by the resonance frequency of the tank circuit.

In the next tutorial about Oscillators, we will look at RC Oscillators which uses resistors and capacitors as its tank circuit to produce a sinusoidal waveform.

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explain briefly about how does colpitts oscillator get their 360° phase shift around the feedback loop.

As explained in the tutorial, oscilator feedback is provided through the capacitor pair that form a voltage divider. This split capacitor LC tank circuit introduces 180° phase shift as each end of the tank circuit are 180° out-of-phase. Then the total phase shift around the loop is 360° since the transistor amplifier itself introduces an additional phase shift of 180°.

what use of RFC in hartley & colpitt oscillator…?

The RF choke acts as a short-circuit to the DC supply allowing collector current to flow, and also as a very high impedance (open-circuit), due to its reactance, isolating the tank circuit and therefore the oscillation frequency from the power supply.

There appears to be a problem with your Colpitts Osillator circuit. If I neglect to connect R1 and R2 to the base of the transistor (and leave everything else the same), I can get the circuit to oscillate at a modulated frequency in SPICE. However, if I do tie R1 and R2 to the base as shown in your circuit, the oscillation is not sustained. Could you please recheck your circuit?

The LC oscillator uses a transistor amplifier which requires biasing. There are different ways to achieve this, but in the simple example above the voltage divider network supplies the forward bias to the base of the transistor. This can also be achieved using self bias techniques with a single biasing resistor providing feedback from the Collector and Base of the transistor.

this is the Answer

Hello wayne storr .

im looking for a 5 to 10MHz Oscillator . can you tell me a suitable one please ?

How I can calculate inductance of the coil L2 in example with transistor?

The value of XL (inductive reactance) at the required oscillation frequency.

When simulating the OpAmp circuit with LTspice, we see that the frequency of oscillation is much lower than expected, say about one tenth (1.7 kHz). Any idea why this could be?

There will be some difference between exactly calculated and measured values. Try a different op-amp and/or components values in your simulation. My circuit simulates at 10,483 Hz (about 3% difference), which is close enough for this basic Colpitts circuit.

am still not able to explain about, why two capacitor are connected in series for colipt oscillator. i need more clarification

they are in parallel

This is the fundamental design concept of a Colpitts Oscillator. If you do not understand why there are two capacitors then may be you need to study another oscillator circuit, or do some more research.

My earlier comment was intended for the common-base oscillator circuit, not the common-emitter Colpitts topology shown here.

A student has had problems getting the circuit to oscillate, and I thought it well to suggest that a problem arises in assuming that the AC impedance of the battery is zero ohms. Unfortunately, that is not the case; a typical 9V battery may have an AC impedance of several ohms, and this most unfortunately appears as a series loss resistance for the inductor, degrading the Q and gain of the circuit. A good remedy is to bypass the battery with a low-loss capacitor of about 0.1 microfarad or more. In the event that adding the bypass does not completely resolve the failure to sustain oscillation, the ratios of values of the two “Colpitts divider” capacitors could be adjusted for optimum gain. Doing this analytically involves taking into account the effective common-base input impedance of the transistor.