**The Op-amp Differentiator Amplifier**

The basic **Op-amp Differentiator** circuit is the exact opposite to that of the Integrator Amplifier circuit that we looked at in the previous tutorial. Here, the position of the capacitor and resistor have been reversed and now the reactance, Xc is connected to the input terminal of the inverting amplifier while the resistor, Rƒ forms the negative feedback element across the operational amplifier as normal.

This operational amplifier circuit performs the mathematical operation of **Differentiation**, that is it “*produces a voltage output which is directly proportional to the input voltage’s rate-of-change with respect to time*“. In other words the faster or larger the change to the input voltage signal, the greater the input current, the greater will be the output voltage change in response, becoming more of a “spike” in shape.

As with the integrator circuit, we have a resistor and capacitor forming an RC Network across the operational amplifier and the reactance ( Xc ) of the capacitor plays a major role in the performance of a **Op-amp Differentiator**.

The input signal to the differentiator is applied to the capacitor. The capacitor blocks any DC content so there is no current flow to the amplifier summing point, X resulting in zero output voltage. The capacitor only allows AC type input voltage changes to pass through and whose frequency is dependant on the rate of change of the input signal.

At low frequencies the reactance of the capacitor is “High” resulting in a low gain ( Rƒ/Xc ) and low output voltage from the op-amp. At higher frequencies the reactance of the capacitor is much lower resulting in a higher gain and higher output voltage from the differentiator amplifier.

However, at high frequencies an op-amp differentiator circuit becomes unstable and will start to oscillate. This is due mainly to the first-order effect, which determines the frequency response of the op-amp circuit causing a second-order response which, at high frequencies gives an output voltage far higher than what would be expected. To avoid this the high frequency gain of the circuit needs to be reduced by adding an additional small value capacitor across the feedback resistor Rƒ.

Ok, some math’s to explain what’s going on!. Since the node voltage of the operational amplifier at its inverting input terminal is zero, the current, i flowing through the capacitor will be given as:

The charge on the capacitor equals Capacitance x Voltage across the capacitor

The rate of change of this charge is

but dQ/dt is the capacitor current i

from which we have an ideal voltage output for the op-amp differentiator is given as:

Therefore, the output voltage Vout is a constant -Rƒ.C times the derivative of the input voltage Vin with respect to time. The minus sign indicates a 180^{o} phase shift because the input signal is connected to the inverting input terminal of the operational amplifier.

One final point to mention, the **Op-amp Differentiator** circuit in its basic form has two main disadvantages compared to the previous operational amplifier integrator circuit. One is that it suffers from instability at high frequencies as mentioned above, and the other is that the capacitive input makes it very susceptible to random noise signals and any noise or harmonics present in the source circuit will be amplified more than the input signal itself. This is because the output is proportional to the slope of the input voltage so some means of limiting the bandwidth in order to achieve closed-loop stability is required

If we apply a constantly changing signal such as a Square-wave, Triangular or Sine-wave type signal to the input of a differentiator amplifier circuit the resultant output signal will be changed and whose final shape is dependant upon the RC time constant of the Resistor/Capacitor combination.

The basic single resistor and single capacitor op-amp differentiator circuit is not widely used to reform the mathematical function of **Differentiation** because of the two inherent faults mentioned above, “Instability” and “Noise”. So in order to reduce the overall closed-loop gain of the circuit at high frequencies, an extra resistor, Rin is added to the input as shown below.

Adding the input resistor Rin limits the differentiators increase in gain at a ratio of Rƒ/Rin. The circuit now acts like a differentiator amplifier at low frequencies and an amplifier with resistive feedback at high frequencies giving much better noise rejection. Additional attenuation of higher frequencies is accomplished by connecting a capacitor Cƒ in parallel with the differentiator feedback resistor, Rƒ. This then forms the basis of a Active High Pass Filter as we have seen before in the filters section.

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I’m good feel…….

GOOD explanation could you please tell me about the concept wireless power transfer ?

Thank you very much, this is helpful more than any textbook

Thank you for the good explanation. Could you please show me how we get the f = 1/(2*pi*RC)

Good

can you please send frequency responce answer numerically as an example with observation table.

pls what of parabola wave?

If you want to input a parabola wave all you need to do is differentiate that wave to find the output. The answer is the derivative of the waveform so its the output.

Vout = -RC dVin/dt

rc differentiator frequency response

send ans

For the square wave input, what is the formula for the amplitude of the spikes at the output of differentiator?

Impulse signal are obtained by differentiating square waves there will slight lag so the slant lines are obtained

The frequency brake points are not shown correctly. A frequency brake point is the point at which the gain of the circuit starts it change, not where it crosses 0 db.

You also call out a C1. I think it should be a Cf.

Other wise a good presentation.

Gerry

Hello Gerry, Its meant to be a generalised bode plot of the filter, but to remove the confusion I have amended the image. Thank you for spotting the typo error, this also has been amended.