In our tutorials about Electromagnetism we saw that when an electrical current flows through a wire conductor, a magnetic flux is developed around the conductor.

This produces a relationship between the direction of this magnetic flux which is circulating around the conductor and the direction of the current flowing through the same conductor resulting in a well known relationship between current and magnetic flux direction called, “Fleming’s Right Hand Rule”.

But there is also another important property relating to a wound coil that also exists, which is that a secondary voltage is induced into the same coil by the movement of the magnetic flux as it opposes or resists any changes in the electrical current flowing it.

A Typical Inductor

In its most basic form, an **Inductor** is nothing more than a coil of wire wound around a central core. For most coils the current, ( i ) flowing through the coil produces a magnetic flux, ( NΦ ) around it that is proportional to this flow of electrical current.

The **Inductor**, also called a choke, is another passive type electrical component which is just a coil of wire that is designed to take advantage of this relationship by inducing a magnetic field in itself or in the core as a result of the current passing through the coil. This results in a much stronger magnetic field than one that would be produced by a simple coil of wire.

Inductors are formed with wire tightly wrapped around a solid central core which can be either a straight cylindrical rod or a continuous loop or ring to concentrate their magnetic flux.

The schematic symbol for a inductor is that of a coil of wire so therefore, a coil of wire can also be called an **Inductor**. Inductors usually are categorised according to the type of inner core they are wound around, for example, hollow core (free air), solid iron core or soft ferrite core with the different core types being distinguished by adding continuous or dotted parallel lines next to the wire coil as shown below.

The current, i that flows through an inductor produces a magnetic flux that is proportional to it. But unlike a Capacitor which oppose a change of voltage across their plates, an inductor opposes the rate of change of current flowing through it due to the build up of self-induced energy within its magnetic field.

In other words, inductors resist or oppose changes of current but will easily pass a steady state DC current. This ability of an inductor to resist changes in current and which also relates current, i with its magnetic flux linkage, NΦ as a constant of proportionality is called **Inductance** which is given the symbol **L** with units of **Henry**, (**H**) after Joseph Henry.

Because the Henry is a relatively large unit of inductance in its own right, for the smaller inductors sub-units of the Henry are used to denote its value. For example:

Prefix |
Symbol |
Multiplier |
Power of Ten |

milli | m | 1/1,000 | 10^{-3} |

micro | µ | 1/1,000,000 | 10^{-6} |

nano | n | 1/1,000,000,000 | 10^{-9} |

So to display the sub-units of the Henry we would use as an example:

- 1mH = 1 milli-Henry – which is equal to one thousandths (1/1000) of an Henry.
- 100uH = 100 micro-Henries – which is equal to 100 millionth’s (1/1,000,000) of a Henry.

Inductors or coils are very common in electrical circuits and there are many factors which determine the inductance of a coil such as the shape of the coil, the number of turns of the insulated wire, the number of layers of wire, the spacing between the turns, the permeability of the core material, the size or cross-sectional area of the core etc, to name a few.

An inductor coil has a central core area, ( A ) with a constant number of turns of wire per unit length, ( l ). So if a coil of N turns is linked by an amount of magnetic flux, Φ then the coil has a flux linkage of NΦ and any current, ( i ) that flows through the coil will produce an induced magnetic flux in the opposite direction to the flow of current. Then according to Faraday’s Law, any change in this magnetic flux linkage produces a self-induced voltage in the single coil of:

- Where:
- N is the number of turns
- A is the cross-sectional Area in m2
- Φ is the amount of flux in Webers
- μ is the Permeability of the core material
- l is the Length of the coil in meters
- di/dt is the Currents rate of change in amps/second

A time varying magnetic field induces a voltage that is proportional to the rate of change of the current producing it with a positive value indicating an increase in emf and a negative value indicating a decrease in emf. The equation relating this self-induced voltage, current and inductance can be found by substituting the μN^{2}A / l with L denoting the constant of proportionality called the **Inductance** of the coil.

The relation between the flux in the inductor and the current flowing through the inductor is given as: Φ = Li. As an inductor consists of a coil of conducting wire, this then reduces the above equation to give the self-induced emf, sometimes called the **back emf** induced in the coil too:

Where: L is the self-inductance and di/dt the rate of current change.

Inductor Coil

So from this equation we can say that the “self-induced emf = inductance x rate of current change” and a circuit has an inductance of one Henry will have an emf of one volt induced in the circuit when the current flowing through the circuit changes at a rate of one ampere per second.

One important point to note about the above equation. It only relates the emf produced across the inductor to changes in current because if the flow of inductor current is constant and not changing such as in a steady state DC current, then the induced emf voltage will be zero because the instantaneous rate of current change is zero, di/dt = 0.

With a steady state DC current flowing through the inductor and therefore zero induced voltage across it, the inductor acts as a short circuit equal to a piece of wire, or at the very least a very low value resistance. In other words, the opposition to the flow of current offered by an inductor is very different between AC and DC circuits.

We now know that the current can not change instantaneously in an inductor because for this to occur, the current would need to change by a finite amount in zero time which would result in the rate of current change being infinite, di/dt = ∞, making the induced emf infinite as well and infinite voltages do no exist. However, if the current flowing through an inductor changes very rapidly, such as with the operation of a switch, high voltages can be induced across the inductors coil.

Consider the circuit of the inductor on the right. With the switch, ( S1 ) open, no current flows through the inductor coil. As no current flows through the inductor, the rate of change of current (di/dt) in the coil will be zero. If the rate of change of current is zero there is no self-induced emf, ( V_{L} = 0 ) within the inductor coil.

If we now close the switch (t = 0), a current will flow through the circuit and slowly rise to its maximum value at a rate determined by the inductance of the inductor. This rate of current flowing through the inductor multiplied by the inductors inductance in Henry’s, results in some fixed value self-induced emf being produced across the coil as determined by Faraday’s equation above, V_{L} = Ldi/dt.

This self-induced emf across the inductors coil, ( V_{L} ) fights against the applied voltage until the current reaches its maximum value and a steady state condition is reached. The current which now flows through the coil is determined only by the DC or “pure” resistance of the coils windings as the reactance value of the coil has decreased to zero because the rate of change of current (di/dt) is zero in steady state. In other words, only the coils DC resistance now exists to oppose the flow of current.

Likewise, if switch, (S1) is opened, the current flowing through the coil will start to fall but the inductor will again fight against this change and try to keep the current flowing at its previous value by inducing a voltage in the other direction. The slope of the fall will be negative and related to the inductance of the coil as shown below.

How much induced voltage will be produced by the inductor depends upon the rate of current change. In our tutorial about Electromagnetic Induction, **Lenz’s Law** stated that: “the direction of an induced emf is such that it will always opposes the change that is causing it”. In other words, an induced emf will always OPPOSE the motion or change which started the induced emf in the first place.

So with a decreasing current the voltage polarity will be acting as a source and with an increasing current the voltage polarity will be acting as a load. So for the same rate of current change through the coil, either increasing or decreasing the magnitude of the induced emf will be the same.

A steady state direct current of 4 ampere passes through a solenoid coil of 0.5H. What would be the back emf voltage induced in the coil if the switch in the above circuit was opened for 10mS and the current flowing through the coil dropped to zero ampere.

We know that an inductor in a circuit opposes the flow of current, ( i ) through it because the flow of this current induces an emf that opposes it, Lenz’s Law. Then work has to be done by the external battery source in order to keep the current flowing against this induced emf. The instantaneous power used in forcing the current, ( i ) against this self-induced emf, ( V_{L} ) is given from above as:

Power in a circuit is given as, P = V.I therefore:

An ideal inductor has no resistance only inductance so R = 0 Ω’s and therefore no power is dissipated within the coil, so we can say that an ideal inductor has zero power loss.

When power flows into an inductor, energy is stored in its magnetic field. When the current flowing through the inductor is increasing and di/dt becomes greater than zero, the instantaneous power in the circuit must also be greater than zero, ( P > 0 ) ie, positive which means that energy is being stored in the inductor.

Likewise, if the current through the inductor is decreasing and di/dt is less than zero then the instantaneous power must also be less than zero, ( P < 0 ) ie, negative which means that the inductor is returning energy back into the circuit. Then by integrating the equation for power above, the total magnetic energy which is always positive, being stored in the inductor is therefore given as:

Where: W is in joules, L is in Henries and i is in Amperes

The energy is actually being stored within the magnetic field that surrounds the inductor by the current flowing through it. In an ideal inductor that has no resistance or capacitance, as the current increases energy flows into the inductor and is stored there within its magnetic field without loss, it is not released until the current decreases and the magnetic field collapses.

Then in an alternating current, AC circuit an inductor is constantly storing and delivering energy on each and every cycle. If the current flowing through the inductor is constant as in a DC circuit, then there is no change in the stored energy as P = Li(di/dt) = 0.

So inductors can be defined as passive components as they can both stored and deliver energy to the circuit, but they cannot generate energy. An ideal inductor is classed as loss less, meaning that it can store energy indefinitely as no energy is lost.

However, real inductors will always have some resistance associated with the windings of the coil and whenever current flows through a resistance energy is lost in the form of heat due to Ohms Law, ( P = I^{2 }R ) regardless of whether the current is alternating or constant.

Then the primary use for inductors is in filtering circuits, resonance circuits and for current limiting. An inductor can be used in circuits to block or reshape alternating current or a range of sinusoidal frequencies, and in this role an inductor can be used to “tune” a simple radio receiver or various types of oscillators. It can also protect sensitive equipment from destructive voltage spikes and high inrush currents.

In the next tutorial about Inductors, we will see that the effective resistance of a coil is called Inductance, and that inductance which as we now know is the characteristic of an electrical conductor that “opposes a change in the current”, can either be internally induced, called self-inductance or externally induced, called mutual-inductance.

Error! Please fill all fields.

If a current of 5 A flowing through a coil of 0.1 H reverses in 10 msec, what will be the emf induced in coil?

50 volts, you can do the maths.

what if I have a 12volts battery and want to built an inductance with a 12volts input and get 50volts on the outside. which sizes of core will I use and how many turn will I use on the input and output of the

Firstly you do not need an inductor, you need a transformer, and transformers will not work from a DC supply unless there is additional circuitry.

what is the reason behind voltage dispersed is high when compered with connected voltage

No, it is not a rheostat. it uses dynamic inductance to vary the currant of two separate feeds being separated by north opposing fields. this allows both feeds to be varied (on up one down) separately but in unison. as the brush rotates (positive) the currant of the two feeds (negative) can be varied in unison one gaining while the other is lowering and viseverse as the brush rotates at 60 hz.

how can i calculate that ???

Mr. Storr,

I have an a large closed loop inductor with one winding on it all around the core. i have two taps on either side left and right. i have a brush that rotates making contact on top with on two wires at a time. the currant is constant value as is voltage, 100 volts 10 amp Dc. how do i calculate the currant drop on right side of brush and rise in currant on left side as the brush rotates right to left.

this is a real device i am working on and need help bad.

thank you,

Donald

Sounds like you have a Rheostat, then you can use the ratio of voltage OUT to voltage IN (100V) and then apply to the current IN (10A) to determine the current either side of the slider.

No, it is not a rheostat. it uses dynamic inductance to vary the currant of two separate feeds being separated by north opposing fields. this allows both feeds to be varied (one up one down) separately but in unison. as the brush rotates (positive) the currant of the two feeds (negative) can be varied in unison one gaining while the other is lowering and viseverse as the brush rotates at 3600 rpm

how can i calculate that ???

Hmmm… the best way to get help with something is to actually give all of the relevant information.

If you have constant current and voltage in the loop (DC), then what part is “dynamic” ? A constant current (after the voltage source is initially connected, and the magnetic has time to max out), means a constant magnetic field.

Are there other coils and cores? Diagrams and pictures would be better to explain…..

It seams your not as smart as you lead on. typical store bought Dogma.

I have no knowledge or experience of the electrical machine to which you refer, and therefore I can not comment on its operation.

Mr. Storr,

Instead of the currant that changes all other parameters being static. the parameters are changing ie. (N) number of turns, (A) square-section of core in meters squared and (I) length in coil in meters, all three being varied over time causing currant variation as the brush rotates.

in an ac circuit if we have an inductor , as the current keeps varying so there will be opposite emf induced in the coil so the current flowing in the circuit should be negligible

y is it not so?

In an AC circuit, the current flowing through an inductor is determined by its reactance at the given frequency.

I thought to produce a voltage you needed relative motion between a magnetic field and conductor. How is a magnetic field produced when their is no conductor?.

There is relative motion between the coil and the current flowing through it as the current is varying with time, therefore the magnetic field is varying with time.

Is there any circumstances where there could be an induced EMF without an induced current?

Your site is very good

Thank you

Yes when the coil is open-circuited.

Nice tutorial, thank you

What happens if you take two toriods of different material and place them side by side and then wind the inductor