We have also seen in our tutorial about series RLC circuits that two or more sinusoidal signals can be combined using phasors providing that they have the same frequency supply.

But what would happen to the characteristics of the circuit if a supply voltage of fixed amplitude but of different frequencies was applied to the circuit. Also what would the circuits “frequency response” behaviour be upon the two reactive components due to this varying frequency.

In a series RLC circuit there becomes a frequency point were the inductive reactance of the inductor becomes equal in value to the capacitive reactance of the capacitor. In other words, X_{L} = X_{C}. The point at which this occurs is called the **Resonant Frequency** point, ( ƒ_{r} ) of the circuit, and as we are analysing a series RLC circuit this resonance frequency produces a **Series Resonance**.

*Series Resonance* circuits are one of the most important circuits used electrical and electronic circuits. They can be found in various forms such as in AC mains filters, noise filters and also in radio and television tuning circuits producing a very selective tuning circuit for the receiving of the different frequency channels. Consider the simple series RLC circuit below.

### Series RLC Circuit

Firstly, let us define what we already know about series RLC circuits.

From the above equation for inductive reactance, if either the **Frequency** or the **Inductance** is increased the overall inductive reactance value of the inductor would also increase. As the frequency approaches infinity the inductors reactance would also increase towards infinity with the circuit element acting like an open circuit.

However, as the frequency approaches zero or DC, the inductors reactance would decrease to zero, causing the opposite effect acting like a short circuit. This means then that inductive reactance is “**Proportional**” to frequency and is small at low frequencies and high at higher frequencies and this demonstrated in the following curve:

### Inductive Reactance against Frequency

The graph of inductive reactance against frequency is a straight line linear curve. The inductive reactance value of an inductor increases linearly as the frequency across it increases. Therefore, inductive reactance is positive and is directly proportional to frequency ( X_{L} ∝ ƒ )

The same is also true for the capacitive reactance formula above but in reverse. If either the **Frequency** or the **Capacitance** is increased the overall capacitive reactance would decrease. As the frequency approaches infinity the capacitors reactance would reduce to zero causing the circuit element to act like a perfect conductor of 0Ω’s.

But as the frequency approaches zero or DC level, the capacitors reactance would rapidly increase up to infinity causing it to act like a very large resistance acting like an open circuit condition. This means then that capacitive reactance is “**Inversely proportional**” to frequency for any given value of capacitance and this shown below:

### Capacitive Reactance against Frequency

The graph of capacitive reactance against frequency is a hyperbolic curve. The Reactance value of a capacitor has a very high value at low frequencies but quickly decreases as the frequency across it increases. Therefore, capacitive reactance is negative and is inversely proportional to frequency ( X_{C} ∝ ƒ ^{-1} )

We can see that the values of these resistances depends upon the frequency of the supply. At a higher frequency X_{L} is high and at a low frequency X_{C} is high. Then there must be a frequency point were the value of X_{L} is the same as the value of X_{C} and there is. If we now place the curve for inductive reactance on top of the curve for capacitive reactance so that both curves are on the same axes, the point of intersection will give us the series resonance frequency point, ( ƒ_{r} or ω_{r} ) as shown below.

### Series Resonance Frequency

where: ƒ_{r} is in Hertz, L is in Henries and C is in Farads.

Electrical resonance occurs in an AC circuit when the two reactances which are opposite and equal cancel each other out as X_{L} = X_{C} and the point on the graph at which this happens is were the two reactance curves cross each other. In a series resonant circuit, the resonant frequency, ƒ_{r} point can be calculated as follows.

We can see then that at resonance, the two reactances cancel each other out thereby making a series LC combination act as a short circuit with the only opposition to current flow in a series resonance circuit being the resistance, R. In complex form, the resonant frequency is the frequency at which the total impedance of a series RLC circuit becomes purely *“real”*, that is no imaginary impedance’s exist. This is because at resonance they are cancelled out. So the total impedance of the series circuit becomes just the value of the resistance and therefore: Z = R.

Then at resonance the impedance of the series circuit is at its minimum value and equal only to the resistance, R of the circuit. The circuit impedance at resonance is called the “dynamic impedance” of the circuit and depending upon the frequency, X_{C} (typically at high frequencies) or X_{L} (typically at low frequencies) will dominate either side of resonance as shown below.

### Impedance in a Series Resonance Circuit

Note that when the capacitive reactance dominates the circuit the impedance curve has a hyperbolic shape to itself, but when the inductive reactance dominates the circuit the curve is non-symmetrical due to the linear response of X_{L}. You may also note that if the circuits impedance is at its minimum at resonance then consequently, the circuits **admittance** must be at its maximum and one of the characteristics of a series resonance circuit is that admittance is very high. But this can be a bad thing because a very low value of resistance at resonance means that the resulting current flowing through the circuit may be dangerously high.

We recall from the previous tutorial about series RLC circuits that the voltage across a series combination is the phasor sum of V_{R}, V_{L} and V_{C}. Then if at resonance the two reactances are equal and cancelling, the two voltages representing V_{L} and V_{C} must also be opposite and equal in value thereby cancelling each other out because with pure components the phasor voltages are drawn at +90^{o} and -90^{o} respectively.

Then in a **series resonance** circuit as V_{L} = -V_{C} the resulting reactive voltages are zero and all the supply voltage is dropped across the resistor. Therefore, V_{R} = V_{supply} and it is for this reason that series resonance circuits are known as voltage resonance circuits, (as opposed to parallel resonance circuits which are current resonance circuits).

### Series RLC Circuit at Resonance

Since the current flowing through a series resonance circuit is the product of voltage divided by impedance, at resonance the impedance, Z is at its minimum value, ( =R ). Therefore, the circuit current at this frequency will be at its maximum value of V/R as shown below.

### Series Circuit Current at Resonance

The frequency response curve of a series resonance circuit shows that the magnitude of the current is a function of frequency and plotting this onto a graph shows us that the response starts at near to zero, reaches maximum value at the resonance frequency when I_{MAX} = I_{R} and then drops again to nearly zero as ƒ becomes infinite. The result of this is that the magnitudes of the voltages across the inductor, L and the capacitor, C can become many times larger than the supply voltage, even at resonance but as they are equal and at opposition they cancel each other out.

As a series resonance circuit only functions on resonant frequency, this type of circuit is also known as an **Acceptor Circuit** because at resonance, the impedance of the circuit is at its minimum so easily accepts the current whose frequency is equal to its resonant frequency.

You may also notice that as the maximum current through the circuit at resonance is limited only by the value of the resistance (a pure and real value), the source voltage and circuit current must therefore be in phase with each other at this frequency. Then the phase angle between the voltage and current of a series resonance circuit is also a function of frequency for a fixed supply voltage and which is zero at the resonant frequency point when: V, I and V_{R} are all in phase with each other as shown below. Consequently, if the phase angle is zero then the power factor must therefore be unity.

### Phase Angle of a Series Resonance Circuit

Notice also, that the phase angle is positive for frequencies above ƒ_{r} and negative for frequencies below ƒ_{r} and this can be proven by,

## Bandwidth of a Series Resonance Circuit

If the series RLC circuit is driven by a variable frequency at a constant voltage, then the magnitude of the current, I is proportional to the impedance, Z, therefore at resonance the power absorbed by the circuit must be at its maximum value as P = I^{2}Z.

If we now reduce or increase the frequency until the average power absorbed by the resistor in the series resonance circuit is half that of its maximum value at resonance, we produce two frequency points called the **half-power points** which are -3dB down from maximum, taking 0dB as the maximum current reference.

These -3dB points give us a current value that is 70.7% of its maximum resonant value which is defined as: 0.5( I^{2} R ) = (0.707 x I)^{2} R. Then the point corresponding to the lower frequency at half the power is called the “lower cut-off frequency”, labelled ƒ_{L} with the point corresponding to the upper frequency at half power being called the “upper cut-off frequency”, labelled ƒ_{H}. The distance between these two points, i.e. ( ƒ_{H} – ƒ_{L} ) is called the **Bandwidth**, (BW) and is the range of frequencies over which at least half of the maximum power and current is provided as shown.

### Bandwidth of a Series Resonance Circuit

The frequency response of the circuits current magnitude above, relates to the “sharpness” of the resonance in a series resonance circuit. The sharpness of the peak is measured quantitatively and is called the **Quality factor, Q** of the circuit. The quality factor relates the maximum or peak energy stored in the circuit (the reactance) to the energy dissipated (the resistance) during each cycle of oscillation meaning that it is a ratio of resonant frequency to bandwidth and the higher the circuit Q, the smaller the bandwidth, Q = ƒ_{r} /BW.

As the bandwidth is taken between the two -3dB points, the **selectivity** of the circuit is a measure of its ability to reject any frequencies either side of these points. A more selective circuit will have a narrower bandwidth whereas a less selective circuit will have a wider bandwidth. The selectivity of a series resonance circuit can be controlled by adjusting the value of the resistance only, keeping all the other components the same, since Q = (X_{L} or X_{C})/R.

### Bandwidth of a Series RLC Resonance Circuit

Then the relationship between resonance, bandwidth, selectivity and quality factor for a series resonance circuit being defined as:

### 1). Resonant Frequency, (ƒ_{r})

### 2). Current, (I)

### 3). Lower cut-off frequency, (ƒ_{L})

### 4). Upper cut-off frequency, (ƒ_{H})

### 5). Bandwidth, (BW)

### 6). Quality Factor, (Q)

## Series Resonance Example No1

A series resonance network consisting of a resistor of 30Ω, a capacitor of 2uF and an inductor of 20mH is connected across a sinusoidal supply voltage which has a constant output of 9 volts at all frequencies. Calculate, the resonant frequency, the current at resonance, the voltage across the inductor and capacitor at resonance, the quality factor and the bandwidth of the circuit. Also sketch the corresponding current waveform for all frequencies.

Resonant Frequency, ƒ_{r}

Circuit Current at Resonance, I_{m}

Inductive Reactance at Resonance, X_{L}

Voltages across the inductor and the capacitor, V_{L}, V_{C}

Note: the supply voltage may be only 9 volts, but at resonance, the reactive voltages across the capacitor, V_{C} and the inductor, V_{L} are 30 volts peak!

Quality factor, Q

Bandwidth, BW

The upper and lower -3dB frequency points, ƒ_{H} and ƒ_{L}

Current Waveform

## Series Resonance Example No2

A series circuit consists of a resistance of 4Ω, an inductance of 500mH and a variable capacitance connected across a 100V, 50Hz supply. Calculate the capacitance require to give series resonance and the voltages generated across both the inductor and the capacitor.

Resonant Frequency, ƒ_{r}

Voltages across the inductor and the capacitor, V_{L}, V_{C}

## Series Resonance Summary

You may have noticed that during the analysis of series resonance circuits in this tutorial, we looked at bandwidth, upper and lower frequencies, -3dB points and quality or Q-factor. All these are terms used in designing and building of Bandpass Filters and indeed, resonance is used in 3-element mains filter design to pass all frequencies within the “passband” range while rejecting all others.

However, the main aim of this tutorial is to analyse and understand the concept of how **Series Resonance** occurs in passive RLC series circuits. Their use in RLC filter networks and designs is outside the scope of this particular tutorial, and so will not be looked at here, sorry.

- For resonance to occur in any circuit it must have at least one inductor and one capacitor.
- Resonance is the result of oscillations in a circuit as stored energy is passed from the inductor to the capacitor.
- Resonance occurs when X
_{L} = X_{C} and the imaginary part of the transfer function is zero.
- At resonance the impedance of the circuit is equal to the resistance value as Z = R.
- At low frequencies the series circuit is capacitive as: X
_{C} > X_{L}, this gives the circuit a leading power factor.
- At high frequencies the series circuit is inductive as: X
_{L} > X_{C}, this gives the circuit a lagging power factor.
- The high value of current at resonance produces very high values of voltage across the inductor and capacitor.
- Series resonance circuits are useful for constructing highly frequency selective filters. However, its high current and very high component voltage values can cause damage to the circuit.
- The most prominent feature of the frequency response of a resonant circuit is a sharp resonant peak in its amplitude characteristics.
- Because impedance is minimum and current is maximum, series resonance circuits are also called
**Acceptor Circuits**.

In the next tutorial about Parallel Resonance we will look at how frequency affects the characteristics of a parallel connected RLC circuit and how this time the Q-factor of a parallel resonant circuit determines its current magnification.

Thank you…, This theory was more helpful..,

Hi; my teacher give us like this question, but there isn’t volt.

How can ı solve without volt. ? thank yu.

Wow very helpful This funda☺☺

Great article, thanks! I noticed that if you find the cutoff frequencies using fr +-1/2BW, you get a slightly different answer than the equations for omegaH and omegaL (that includes the resistor) and divide by 2pi. The difference is only a few Hz, but which one is correct?

It depends how accurate you want to be as +-1/2BW will give you perfectly centered values around the resonant frequency.

Love this website btw. Have read and reread many of your articles. I built a simple RLC circuit and connected it to a simulated sinusoidal waveform (EE Board and Waveform Software) because I wanted to see physical data from varying frequencies and measured the peak voltages at the capacitor. My data is misleading though. At the calculated resonant frequency my output voltage is roughly half the input voltage which I find strange because that value is similar to the output voltage at same frequency in just an RC circuit where there should be no resonance, therefore no max current across the capacitor. Using a smaller value resistor in the RLC circuit produced results closer to what you were talking about where the output voltage becomes greater then the input frequency, however it was just higher then the calculated resonate frequency.

First circuit was

1500 ohm

1mH

4.7uF

Replaced resistor with a 100 ohm and that is when I got increasing voltage across the capacitor.

Either my data was wrong or my calculations were wrong.

I think the problem you have here is that the capacitance value, 4.7pF is too low. 4.7pF is virtually nothing. At your high resonant frequency of 2.32MHz, energy is being passed between the capacitor and the inductor but very little. Also at this frequency, XL and Xc are very high, along with your 1k5 resistor very little current is flowing in the circuit.

*Edit to my original post*

That was a 4.7pF

And it was a 1Vpeak input

plz explain this…………

In RLC ckt Z is maximum at low frequency when…………

a) Xc is small

b)Xc is large

c)XL is small

d)XL is large

Instead of just blindly posting the same homework question multiple times, think about it a little, its called learning. At high frequencies, for a given L and C, inductive reactance, XL (2pifL) is High and capacitive reatance, Xc (1/2pifC) is Low. At low frequencies the reverse, as XL is Low and Xc is High. So which one do you think it is.

Very useful site.please create a platform so students can post questions.

It already exists at the bottom of every tutorial.

Thank you it was help full.

great content, I had to go through before my Master’s degree in EEE final exam .

Its helpfu

Thanks.