In a pure ohmic resistor the voltage waveforms are “inphase” with the current. In a pure inductance the voltage waveform “leads” the current by 90^{o}, giving us the expression of: ELI. In a pure capacitance the voltage waveform “lags” the current by 90^{o}, giving us the expression of: ICE.
This Phase Difference, Φ depends upon the reactive value of the components being used and hopefully by now we know that reactance, ( X ) is zero if the circuit element is resistive, positive if the circuit element is inductive and negative if it is capacitive thus giving their resulting impedances as:
Element Impedance
Circuit Element 
Resistance, (R) 
Reactance, (X) 
Impedance, (Z) 
Resistor 
R 
0 

Inductor 
0 
ωL 

Capacitor 
0 


Instead of analysing each passive element separately, we can combine all three together into a series RLC circuit. The analysis of a series RLC circuit is the same as that for the dual series R_{L} and R_{C} circuits we looked at previously, except this time we need to take into account the magnitudes of both X_{L} and X_{C} to find the overall circuit reactance. Series RLC circuits are classed as secondorder circuits because they contain two energy storage elements, an inductance L and a capacitance C. Consider the RLC circuit below.
Series RLC Circuit
The series RLC circuit above has a single loop with the instantaneous current flowing through the loop being the same for each circuit element. Since the inductive and capacitive reactance’s X_{L} and X_{C} are a function of the supply frequency, the sinusoidal response of a series RLC circuit will therefore vary with frequency, ƒ. Then the individual voltage drops across each circuit element of R, L and C element will be “outofphase” with each other as defined by:
 i_{(t)} = I_{max} sin(ωt)
 The instantaneous voltage across a pure resistor, V_{R} is “inphase” with the current.
 The instantaneous voltage across a pure inductor, V_{L} “leads” the current by 90^{o}
 The instantaneous voltage across a pure capacitor, V_{C} “lags” the current by 90^{o}
 Therefore, V_{L} and V_{C} are 180^{o} “outofphase” and in opposition to each other.
For the series RLC circuit above, this can be shown as:
The amplitude of the source voltage across all three components in a series RLC circuit is made up of the three individual component voltages, V_{R}, V_{L} and V_{C} with the current common to all three components. The vector diagrams will therefore have the current vector as their reference with the three voltage vectors being plotted with respect to this reference as shown below.
Individual Voltage Vectors
This means then that we can not simply add together V_{R}, V_{L} and V_{C} to find the supply voltage, V_{S} across all three components as all three voltage vectors point in different directions with regards to the current vector. Therefore we will have to find the supply voltage, V_{S} as the Phasor Sum of the three component voltages combined together vectorially.
Kirchoff’s voltage law ( KVL ) for both loop and nodal circuits states that around any closed loop the sum of voltage drops around the loop equals the sum of the EMF’s. Then applying this law to the these three voltages will give us the amplitude of the source voltage, V_{S} as.
Instantaneous Voltages for a Series RLC Circuit
The phasor diagram for a series RLC circuit is produced by combining together the three individual phasors above and adding these voltages vectorially. Since the current flowing through the circuit is common to all three circuit elements we can use this as the reference vector with the three voltage vectors drawn relative to this at their corresponding angles.
The resulting vector V_{S} is obtained by adding together two of the vectors, V_{L} and V_{C} and then adding this sum to the remaining vector V_{R}. The resulting angle obtained between V_{S} and i will be the circuits phase angle as shown below.
Phasor Diagram for a Series RLC Circuit
We can see from the phasor diagram on the right hand side above that the voltage vectors produce a rectangular triangle, comprising of hypotenuse V_{S}, horizontal axis V_{R} and vertical axis V_{L} – V_{C} Hopefully you will notice then, that this forms our old favourite the Voltage Triangle and we can therefore use Pythagoras’s theorem on this voltage triangle to mathematically obtain the value of V_{S} as shown.
Voltage Triangle for a Series RLC Circuit
Please note that when using the above equation, the final reactive voltage must always be positive in value, that is the smallest voltage must always be taken away from the largest voltage we can not have a negative voltage added to V_{R} so it is correct to have V_{L} – V_{C} or V_{C} – V_{L}. The smallest value from the largest otherwise the calculation of V_{S} will be incorrect.
We know from above that the current has the same amplitude and phase in all the components of a series RLC circuit. Then the voltage across each component can also be described mathematically according to the current flowing through, and the voltage across each element as.
By substituting these values into Pythagoras’s equation above for the voltage triangle will give us:
So we can see that the amplitude of the source voltage is proportional to the amplitude of the current flowing through the circuit. This proportionality constant is called the Impedance of the circuit which ultimately depends upon the resistance and the inductive and capacitive reactance’s.
Then in the series RLC circuit above, it can be seen that the opposition to current flow is made up of three components, X_{L}, X_{C} and R with the reactance, X_{T} of any series RLC circuit being defined as: X_{T} = X_{L} – X_{C} or X_{T} = X_{C} – X_{L} with the total impedance of the circuit being thought of as the voltage source required to drive a current through it.
The Impedance of a Series RLC Circuit
As the three vector voltages are outofphase with each other, X_{L}, X_{C} and R must also be “outofphase” with each other with the relationship between R, X_{L} and X_{C} being the vector sum of these three components thereby giving us the circuits overall impedance, Z. These circuit impedance’s can be drawn and represented by an Impedance Triangle as shown below.
The Impedance Triangle for a Series RLC Circuit
The impedance Z of a series RLC circuit depends upon the angular frequency, ω as do X_{L} and X_{C} If the capacitive reactance is greater than the inductive reactance, X_{C} > X_{L} then the overall circuit reactance is capacitive giving a leading phase angle. Likewise, if the inductive reactance is greater than the capacitive reactance, X_{L} > X_{C} then the overall circuit reactance is inductive giving the series circuit a lagging phase angle. If the two reactance’s are the same and X_{L} = X_{C} then the angular frequency at which this occurs is called the resonant frequency and produces the effect of resonance which we will look at in more detail in another tutorial.
Then the magnitude of the current depends upon the frequency applied to the series RLC circuit. When impedance, Z is at its maximum, the current is a minimum and likewise, when Z is at its minimum, the current is at maximum. So the above equation for impedance can be rewritten as:
The phase angle, θ between the source voltage, V_{S} and the current, i is the same as for the angle between Z and R in the impedance triangle. This phase angle may be positive or negative in value depending on whether the source voltage leads or lags the circuit current and can be calculated mathematically from the ohmic values of the impedance triangle as:
Series RLC Circuit Example No1
A series RLC circuit containing a resistance of 12Ω, an inductance of 0.15H and a capacitor of 100uF are connected in series across a 100V, 50Hz supply. Calculate the total circuit impedance, the circuits current, power factor and draw the voltage phasor diagram.
Inductive Reactance, X_{L}.
Capacitive Reactance, X_{C}.
Circuit Impedance, Z.
Circuits Current, I.
Voltages across the Series RLC Circuit, V_{R}, V_{L}, V_{C}.
Circuits Power factor and Phase Angle, θ.
Phasor Diagram.
Since the phase angle θ is calculated as a positive value of 51.8^{o} the overall reactance of the circuit must be inductive. As we have taken the current vector as our reference vector in a series RLC circuit, then the current “lags” the source voltage by 51.8^{o} so we can say that the phase angle is lagging as confirmed by our mnemonic expression “ELI”.
Series RLC Circuit Summary
In a series RLC circuit containing a resistor, an inductor and a capacitor the source voltage V_{S} is the phasor sum made up of three components, V_{R}, V_{L} and V_{C} with the current common to all three. Since the current is common to all three components it is used as the horizontal reference when constructing a voltage triangle.
The impedance of the circuit is the total opposition to the flow of current. For a series RLC circuit, and impedance triangle can be drawn by dividing each side of the voltage triangle by its current, I. The voltage drop across the resistive element is equal to I x R, the voltage across the two reactive elements is I x X = I x X_{L} – I x X_{C} while the source voltage is equal to I x Z. The angle between V_{S} and I will be the phase angle, θ.
When working with a series RLC circuit containing multiple resistances, capacitance’s or inductance’s either pure or impure, they can be all added together to form a single component. For example all resistances are added together, R_{T} = ( R_{1} + R_{2} + R_{3} )…etc or all the inductance’s L_{T} = ( L_{1} + L_{2} + L_{3} )…etc this way a circuit containing many elements can be easily reduced to a single impedance.
In the next tutorial about Parallel RLC Circuits we will look at the voltagecurrent relationship of the three components connected together this time in a parallel circuit configuration when a steady state sinusoidal AC waveform is applied along with the corresponding phasor diagram representation. We will also introduce the concept of Admittance for the first time.
Can you illustrate more examples?? A bit complicated either?!
I loveing for electronics solution. Knowledge is power.0
Knowledge is power
Good
Thanks, it helped me to understand this topic
Thanks, it helped me to understand this topic. I missed its lecture. ðŸ™‚
Very good stuff
English only
To learn something from you
Thanks